For a given number n count trailing zeroes of n!

Fact:

• Zero comes with 10 and
• 10 comes with multiplication of 2 and 5 multiples.
• And 2’s will always be higher than 5 multiple in n!
• so, count only number of 5.

Algorithm:

• Iterate number from 5 to n
  • Counter number for 5 occurred

Latest Source Code:
Github: FactorialTrailingZeroesCounter.java

Output: